an 11.0 gram sample of cacl2 is dissolved in 125 g of water with both substances at 25.0 c. calculate the final tmeperature of the solution assuming no heat lost to the surroundings and assuming the solution has a specific heat capacity of 4.18j/gc

Respuesta :

40.4 C

So far q(rxn) = q(water) + q(CaCl2) (136g)(4.184J/°Cg)(Tfinal - 25.0°C) = (125g)(4.184)(Tfinal - 25.0°c) + (11g)c(Tfinal - 25.0°C).

The specific heat capacity is measured in J/(kg K) or J/(kg °C), and it is the amount of heat (J) absorbed per unit mass (kg) of the material when its temperature rises by 1 K (or 1 °C).The average kinetic energy of the atoms or molecules in the system is measured by temperatures. The zeroth law of thermodynamics states that when two objects are in thermal equilibrium, no heat is transferred between them, resulting in an equalisation of their temperatures.

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