A 90% confidence interval for the average speed of all drivers on interstate 94 is (73.69, 76.31)
Given that,
Imagine asking a sample of 16 people how quickly they travel on Interstate 94. You determine the average speed to be 75 mph and the variance to be 9 mph after gathering your sample.
Solution is as given below :
90% Confidence Interval for μ is
μ = X ± tₐ/2 (n-1) 5/[tex]\sqrt{n}[/tex]
μ = 75 ± (1.75) * 3/[tex]\sqrt{16}[/tex]
μ = (73.69, 76.31)
Consequently, a 90% confidence interval for the interstate 94 average speed of all drivers is μ = (73.69, 76.31)
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