Respuesta :
The pit [2, 2]'s prior probability tends to be 0 and its posterior probability tends to be 1.
Compute the probabilities of Pits Each square in the Wumpus world do consist of a pit with the probability of 0.01 and consist of independent contents of the squares.
As suppose there are total of N/2 pits that are scattered randomly among the total of N squares. To compute the probabilities of the pits in [1, 3] and [2,2], consider that the probabilities of the assignments to complete where the other assignments doesn't gets off.
Thus, the total number of the 3-pit assignment rather remains consistent with the three assigned partial assignments here P 1,3 =true.Thus, in 21 assignment completes when the P 1,3 =true. Next the 55 assignment completes when the
P 1,3, = false.
Thus, it gives P(P 1.3 ) = a' (0.01(0.0001+0.0099+0.0099), 0.99(0.0001+ 0.0099)) = (0.1674, 0.8326)
While when the value of Pay = true, then there are basically four assignments that are partialenough with the total value of 0.0001, 0.0099, 0.0099, 0.9801, through the assignment gets completed.
Next when the value of Pa, = false, then there is only a single assignment that is partial with the value of 0.0001 that completes the assignments. Thus, then the final value of P (P2.2 ) is given asP(P2.2) = a' (0.01(0.0001+ 0.0099+0.0099+0.9801), 0.99x 0.0001) = (0.9902, 0.0098
Thus, the prior probability of the pit [2, 2] tends to be 0 and the posterior probability tends to be one (1).
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