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according to the ideal gas law, a 0.9686 mol sample of oxygen gas in a 1.309 l container at 270.9 k should exert a pressure of 16.45 atm. what is the percent difference between the pressure calculated using the van der waals' equation and the ideal pressure?

Respuesta :

The percent difference between the pressure calculated using the van der waals' equation and the ideal pressure is 5.89 %.

This can be calculated using van der waals' equation, followed by calculating pressure difference by: [P(ideal)-P(Van der waal's equation)/P(ideal)]*100

P(ideal) is given: 16.45

P(van der waals'): [tex](P+n2aV2)(V−nb)=nRT[/tex]

T= 270.9K  

V=1.301 L

a for oxygen = 1.36 (L2 atm mol-2)

b for oxygen =  0.0319 (L mol-1)

n= 0.9686 mol

Using equation P(van der waals's) = 15.48 bar

and difference is 5.81%

To know more about van der Waals' equation, click here,

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