if 2.50g of the organic fuel was reacted with 2.50g of oxygen and 1.00g of water was actually produced, what is the percent yield of this reaction?

Respuesta :

The percent yield would be 40% if 2.50g of the organic fuel was reacted with 2.50g of oxygen and 1.00g of water was produced.

How is the percent yield of an organic molecule determined?

  • The percentage yield is a figure generated to represent the discrepancy between an experiment's theoretical and actual yields.
  • There are by-products and desired products while experimenting with various solutions or producing chemical solutions.
  • To calculate the yield percentage: Multiply by 100 after dividing the actual yield obtained in the lab by the estimated theoretical yield.
  • For instance, your percent yield would be as follows if you started with 100 grams of compound A and produced 80 grams of product B: 80% yield is equal to (80 grams B / 100 grams A) × 100.

To learn more about percent yield, follow the link https://brainly.com/question/12704041

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