The likelihood that at least 150 people will collaborate and react in a fresh sample of 400 telephone numbers is 0.9953.
The probability informs us of the likelihood that an event will occur. It is necessary for the likelihood to fall between 0 and 1. The likelihood of success is 1, whereas the probability of failure is 0.
Given, that the market research company has a history of having a 44% response rate for its telephone surveys.
Therefore, p=44%=0.44=μ
n=400
p=150/400
p=0.375
The standard deviation is then equal to,
σ=√(p(1-p))/n
σ=√(0.44(1-0.44))/400
σ=√(0.44×0.56)/400
σ=0.025
Using the z-table, the values are as follows:
z=(p-μ)/σ
z=(0.375-0.44)/0.025
z=-2.6
p(p>0.375)
=p(z>-2.6)
=1-p(z<-2.6)
=1-0.0047
=0.9953
=99.53%
Therefore, the likelihood that at least 150 people will participate and provide information in a new sample of 400 telephone numbers
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