The minimum amount of oxygen required, in g, for complete combustion of C₅₇H₁₁₀O₆ will be 1304 g
Molecular formula = C₅₇H₁₁₀O₆
The amount is not given so we take it as 1 mol
The minimum amount of oxygen required for combustion = ?
First, we will write the chemical equation
C₅₇H₁₁₀O₆ + O₂ = CO₂ + H₂O
Balance the chemical equation
2C₅₇H₁₁₀O₆ + 163O₂ = 114CO₂ + 110H₂O
The molar ratio of C₅₇H₁₁₀O₆ to oxygen is 2 : 163
As we have 1 mol C₅₇H₁₁₀O₆; 163 / 2 = 81.5 mol
number of moles of O₂ required = 81.5 mol
Covert the number of moles to grams
grams = number of moles × molar mass
grams of O₂ required = 81.5 mol × 16 g/mol
grams of O₂ required = 1304 g
You can also learn about the combustion of organic compounds from the following question:
https://brainly.com/question/20367202
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