a lab worker wishes to dilute 5.00 x 102 ml of 18.0 m hcl to a concentration of 0.25 m. what volume of distilled water (l) must they add to the initial solution to achieve this lower concentration?

Respuesta :

The volume of distilled water they must add to the initial solution to achieve this lower concentration is 35.5 l.

Dilution is defined as the process in which the concentration of a sample is decreased by adding more solvent. The dilution formula is given below.

C₁V₁ = C₂V₂

where C₁ = initial concentration of sample = 18.0 m

V₁ = initial volume of sample = 5.00 x 10² ml

C₂ = final concentration after dilution = 0.25 m

V₂ = total final volume after dilution

Plug in the values to the formula and solve for the final volume.

C₁V₁ = C₂V₂

(18.0 m)(5.00 x 10² ml) = (0.25 m)V₂

V₂ = 36000 ml

Subtract the initial volume from the final volume to determine the volume of water needed to add.

V of water = V₂ - V₁

V of water = 36000 ml - 5.00 x 10² ml

V of water = 35500ml = 35.5 l

Learn more about dilution here: brainly.com/question/1615979

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