Respuesta :
The theoretical yield in grams for this reaction under the given conditions is 11.05g.
What is theoretical yield?
The theoretical yield is the greatest amount of a product that can be produced in a chemical reaction. It can be determined using the chemical equation with balance. the relative formula mass, mass, and mass of the limiting reactant, as well as the relative formula mass of the result
Given,
Mass of H₂ = 1.96 g
Mass of N₂ = 9.78 g
Molar mass of H₂ = 2 g/mol
Molar mass of N₂ = 28 g/mol
Lets calculate the moles of N₂ and H₂,
Moles of H₂ = [tex]\frac{given mass}{molar mass}[/tex]
H₂ = [tex]\frac{1.96}{2}[/tex]
H₂ = 0.98 mol
same for moles of N₂ = [tex]\frac{given mass}{molar mass}[/tex]
N₂ = [tex]\frac{9.78}{28}[/tex]
N₂ = 0.349 mol
Now, calculate limiting and excess reagent.
The balanced chemical equation is:
3H₂ + N₂ = 2NH₃
From the balanced reaction we conclude that.
As, 3 mole of H₂ react 1 mole of N₂
So, 0.98 moles of H₂ react with 0.98/3 = 0.32 moles of N₂
From this we conclude that, N₂ is an excess reagent because the given moles are greater than the required moles and H₂ is a limiting reagent and it limits the formation of product.
Let us calculate the moles of NH₃
From the reaction, we conclude that
As, 3 mole of H₂ react to give 2 mole of NH₃
So, 0.98 mole of H₂ react to give [tex]\frac{2}{3}[/tex]×0.98 = 0.65 mole of NH₃
Now we have to calculate the mass of NH₃
Mass of NH₃ = Moles of NH₃ × Moles of NH₃
Molar mass of NH₃ = 17 g/m
Mass of NH₃ = 0.65 × 17
Mass of NH₃ = 11.05g
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