The expected number of customers that get back their own hat is 1.
Utilizing indicator random variables, we resolve this issue. For 1 ≤ i ≤ n,
Let .
Xi = I {Customer 'i' who gets his hat back itself}.
The number of clients that receive their own hats back should be the random variable X. We want to figure out E[X].
Clearly,
n
X = ∑ Xi
i=1
It is clear that 1/n represents the likelihood that customer 'I' will receive his own hat.
Due to the fundamental characteristics of indicator random variables, this means that E[Xi] = 1/n.
n
E[X] = E [ ∑ Xi ]
i=1
n
= ∑ 1/n
i=1
Put the limits.
E[X] = 1
As a result, 1 consumer is anticipated to have their own hats back.
To know more about the random variables, here
https://brainly.com/question/14356285
#SPJ4