Respuesta :
The energy stored by the capacitor decreases by 1/K J.
A capacitor is a device that shops electrical electricity in an electric-powered discipline by virtue of gathering electric prices on close surfaces insulated from each other. it's miles a passive electronic thing with terminals. The impact of a capacitor is known as capacitance.
Calculation:-
Energy stored in an air-filled Capacitor = 30 J
= Q²/2C = U = 30 J
Now, the power source is disconnected and the dielectric is inserted.
Since there is no source to provide a charge, So charge remains constant.
Noe, capacitance is increased to K times of initial capacitance
C' = KC
U' = Q²/2C'
= Q²/2KC
= 1/k (Q²/2C)
= 1/K × 30
= 30/K J
Hence, the energy decreases with the inserting dielectric.
The capacitor is a device for storing electrical power, along with two conductors in near proximity and insulated from every other. A simple instance of this type of storage tool is the parallel-plate capacitor. the main function of capacitors is to save electrostatic electricity in an electric area, and deliver this power to the circuit, when vital. They allow the AC to skip but block the drift of DC to avoid a risky breakdown of the circuit.
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