5.18 grams of methane will occupy same volume as 0.0325 moles of propane.
The ideal gas equation says,
PV = nRT
Where,
P is pressure, V is volume, n is moles, R is gas constant, T is temperature.
Moles of propane is 0.0325 moles.
volume of propane at 1 atm and 298 K is,
V = nRT/P
V = 0.0325 x 0.082 x 298/1
V = 7.92 L
Volume of propane is 7.92 L.
we know, moles = mass/molar mass.
Molar mass of Methane is 16g/mol.
Moles of methane = mass/16
Volume of methane,
V = nRT/P
7.92 = mass x 0.082 x 298/16
Mass = 5.18grams.
So, 5.18 grams of methane will have same volume as that of 0.0325 moles of propane.
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