9.148 mol sample of nitrogen gas is maintained in a 0.8008 l container at 303.6 k. the pressure in atm is 330 atm.
The van der waal's equation is given as :
( P + ( an² / V² )) ( V - nb ) = RT
P = ( nRT / (V - nb )) - ( an² / V² )
n = 9.418
V = 0.8008 L
T = 303.6 K
a = 1.39 L² mol⁻² atm
b = 3.91 × 10⁻² L mol⁻¹ atm⁻¹
R = 0.821 L atm K⁻¹ mol⁻¹
P = ( 9.418 ×0.821 × 303.6 / ( 0.8008 - 9.148 × 3.91 × 10⁻² ) - ( 1.39 ×
(9.148)²/(0.8008)²
P = 330 atm
Thus, 9.148 mol sample of nitrogen gas is maintained in a 0.8008 l container at 303.6 k. the pressure in atm is 330 atm.
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