The crate needs to put in 1000.63 Joule of work in order to shift its velocity from 0 to 6.67 m/s in the direction of 63.00 south-east.
We are aware that the definition of labor is the multiplication of the force operating in the direction of the displacement (d) and its component.
Given,
A 22 kg container is initially traveling 440 degrees west of north at a speed of 3.90 m/s.
the cosine formula was used to compute the outcome velocity.
where angle ∅ = 440 + 90 + 63 = 593°
v² = (3.90)²+(6.67)² - 2(3.9)(6.67) cos 593
v² = 59.6989 + 52.026 × 0.601
v² = 59.6989 + 31.2676
v² = 90.9665
Resultant velocity V = 9.5376
V = 9.53 m/s
To calculate the much work that must be done on the crate to change its velocity to 6.67 m/s in a direction 63.0° south of east, Because energy and labor are equivalent, the kinetic energy formula is used.
W = 1/2mv²
Where,
m = 22 kg and
v = resultant velocity = 9.53 m/s
W = 0.5 x 22 x (9.53)²
W = 1000.63 Joule
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