At confidence, how large a sample should be taken to obtain a margin of error for the estimation of a population proportion? We now assume that past data are not available for developing a planning value for
Preliminary estimate for proportion (Not Known) is equal to 0.5
Margin of error = E = 0.03
Level of significance = 1-0.99 = 0.01
Z critical value is considered as (by using Z table) = 2.576
So, the sample size formula is taken as
n = [p(1 – p)][tex]\left[Z/E]^{2}[/tex]
=[0.5*(1-0.5)] [2.576/0.03][tex]^{2}[/tex]
=1,843.03
Hence, the sample size is approximately will be 1,844
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