Using the probability, if you choose two cards out of a deck of cards, then the chances one is a red face card and the other is a black non-face card is 1/2.
In the given question,
If you choose two cards out of a deck of cards, then we have to find the chances one is a red face card and the other is a black non-face card.
As we know that in a deck having 52 cards. In which 26 are red and 26 are black.
We have to choose a red face card.
As we know that in a deck have 12 face cards. In which 6 red face cards and 6 black face cards.
So the chance of getting red face card is
P(R)=Total number of red face cards/Total number of cards
P(R)=6/52
We have to choose a black non-face card.
We know that in a deck have 6 black face cards and total black cards are 26. So the non face cards are 20.
So the chance of getting black non-face card is
P(B)=Total number of black non-face cards/Total number of cards
P(B)=20/52
Now the chances of getting one is a red face card and the other is a black non-face card is
P(R or B)=P(R)+P(B)
P(R or B)=6/52+20/52
P(R or B)=(6+20)/52
P(R or B)=26/52
P(R or B)=1/2
Hence, if you choose two cards out of a deck of cards, then the chances one is a red face card and the other is a black non-face card is 1/2.
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