Suppose a distant galaxy has a recessional velocity of 8254 km/s. What is its distance given that the hubble constant is 70 km/s/mpc? input your answer as a number only, in units of mpc.

Respuesta :

Galaxy distance is 118 mpc.

Given:

Suppose a distant galaxy has a recessional velocity of 8254 km/s. What is its distance given that the hubble constant is 70 km/s/mpc.

According to hubble's law:

v = [tex]H_0\\[/tex] * D

where

v = velocity = 8254

[tex]H_0\\[/tex] = hubble constant = 70

D = v/[tex]H_0\\[/tex]

= 8254/70

= 4127/35

= 117.91

≈ 118 mpc.

Therefore Galaxy distance is 118 mpc.

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