The molecular formula for the empirical formula (CHCl[tex])_{n}[/tex] is C2H2Cl2.
Here we have to find the molecular formula.
Form the ideal gas law we have:
PV = nRT
n = moles = weight(W) / molar mass(M)
PV = WRT/ M
Given:
W = 0.8g
R = 0.0821 atm/ K-mol
T = 373K
V = 256mL = 0.256L
P = 750 torr = 750 / 760
= 0.987 atm
Putting all the values we have:
0.987 × 0.256 = 0.8 × 0.0821 × 373 / M
M = 97 g/mol
As the empirical formula is (CHCl[tex])_{n}[/tex]
Molar mass = n ( 12.01 + 1.01 + 35.45)
So we have
97 = n( 48.47)
n = 2
So we have the molecular formula is (CHCl[tex])_{2}[/tex].
Therefore we get the molecular formula is C2H2Cl2.
To know more about the molecular formula refer to the link given below:
https://brainly.com/question/26388921
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