The volume in liters of a 1.29 mol/ L iron(ii) bromide solution that contains 0.275 moles of iron(ii) bromide is 213 mL.
given that :
molarity of iron(ii) bromide solution = 1.29 mol/L
moles of iron(ii) bromide in solution = 0.275 mol
the molarity expression is as follows :
molarity = moles / volume in L
volume in L = moles / molarity
= 0.275 / 1.29
= 0.213 mL = 213 mL
the volume of iron(ii) bromide solution is 213 mL.
Thus, The volume in liters of a 1.29 mol/ L iron(ii) bromide solution that contains 0.275 moles of iron(ii) bromide is 213 mL.
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