The 15.60% of acetic acid is in the dissociated form of the solution.
The chemical equation for the dissociation of acetic acid is the following:
CH₃COOH + H₂O ⇄ H₃O⁺ +CH₃COO⁻
To find the fraction of acetic acid that is in the dissociated form (f), we can apply the following equation. This equation comes from solving the equation of the equilibrium constant for the dissociated fraction of acetic acid:
The value of dissociation constant of acetic acid
Ka for acetic acid = 1.76 x 10⁻⁵
C is concentration, 0.61mM
[tex]f=\frac{-K\alpha + \sqrt{K\alpha ^{2}+ 4K\alpha C } }{2C} \\f= \frac{-1.76X10^{-5} + \sqrt{(1.76X10^{-5}) ^{2}+ 4(1.76X10^{-5}) (0.61X 10^{-3} ) } }{2(0.61X 10^{-3} )} \\[/tex]
f = 0.1560
in percent 0.1560 is 15.60%, so
The 15.60% of acetic acid is in the dissociated form of the solution.
learn more about dissociated form here : https://brainly.com/question/14740746
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