The amount of 4.86 ml needed to completely react with 11.73 ml of 1.006 m ca(oh)2 is 4.86 ml.
given data to be calculated:-
Ca3(PO4)2 (s) + 6H2O can be used to calculate this: 3Ca(OH)2 (aq) + 2H3PO4 (aq) (l)
ca moles (OH)
2 present 11.00 moles of H3PO4 are required; 7.33 moles of H3PO4 in a volume of ml are required; 7.33/1.508 = 4.86.
The direction that creates more moles of gas benefits from an increase in volume, and since there are more moles of products in this case, the reaction will shift to the right and produce more moles of products.
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