The equation of the line passing through the point (2,6) and perpendicular to the given line is y = 6.
Given data;
The line is horizontal, and the slope of the line is infinity.
The slope of the line perpendicular will be expressed as [tex]\frac{-1}{∞}[/tex] = 0
To get the equation of the line and passes through the point (2,6),
A line's equation in point-slope form is written as;
[tex]m = \frac{y-yo}{x-xo}[/tex]
As m is the slope of the line then,
The required equation will be:
y - 6 = 0*(x-2)
y - 6 = 0
y = 6
Hence, the equation of the line that is perpendicular to the given line and passes through the point (2,6) is y = 6.
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