Suppose that on a hot and sticky afternoon in the spring, a tornado passes over the high school. If the air pressure in the lab (volume of 180 m 3 ) was 1. 1 atm before the storm and 0. 85 atm during the storm, to what volume would the laboratory try to expand in order to make up for the large pressure difference outside? 1,800 m 3 230 m 3 7,100 m 3 190 m 3.

Boyle's Law states that the volume of a given mass of a gas is inversely proportional to pressure at constant temperature. V is inversely proportional to P. both V and P are constant.

V1 P1 = V2 P2

Where, p1=initial pressure

V1= initial volume

P2 =final pressure

V2= final volume

Here, p1 is 1.1atm p2 is 0.85 atm v1 is 180m3 .

Putting these values in the expression

1.1atm * 180m3 = 0.85atm *V2

V2= (1.1atm . 180m3) /0.85atm

= 233m3

Hence, 233m3 of gas is needed to expand in order to make up for the large pressure difference outside.

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