Respuesta :
If 17.4 kg of al2o3(s), 51.4 kg of NaOH(l), and 51.4 kg of HF (g) react completely. 89.95 kg of cryolite will be produced.
What is cryolite?
It is synthesized by fusion of sodium fluoride and aluminum fluoride as a electrolyte in the reduction of alumina to aluminum metal
Given data:
mass of Al = 17.4 kg = 17.4 × 10³
mass of NaOH = 51.4kg = 51.4 × 10³
mass of HF = 51.4kg = 51.4 × 10³
Molar mass of Al₂O₃ = 102 g/mol,
Molar mass of NaOH = 40g/mol
Molar mass of HF = 20g/mol
Reaction:
Al₂O₃ + 6 NaOH + 12 HF → 2 Na₂AlF₆ + 9H₂P
Moles of:
- Al₂O₃ : 17.4 × 10³ / 102
- NaOH : 51.4 × 10³ / 240
- HF : 51.4 × 10³ / 240
Mole/ stoichiometry of:
Al₂O₃ : 0.17 × 10³ / 1 = 0.17 × 10³
NaOH : 0.214 × 10³ / 6 = 0.035 × 10³
HF : 0.214× 10³ /12 = 0.017 × 10³
As the mole/ stoichiometric ratio is smallest for HF, it is the limiting reagent.
Molar mass of cryolite is 210gmol and HF is 20g/mol
12 mol of HF = 2 mol of Na₃AlF₆
240 g of HF = 420 g of Na₃AlF₆
51.4 × 10³g of HF = (51.4 × 10³ × 420) / 240
= 89.95 × 10³ g or 89.95 kg of Na₃AlF₆
Hence, 89.95 kg of cryolite is produced.
Learn more about limiting reagent at https://brainly.com/question/23661051
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