g if the standard deviation of the lifetimes of television tubes is estimated to be 100 h, how large a sample must we take in order to be (a) 95%, (b) 99%, and (c) 99.73% confident that the error in the estimated mean lifetime will not exceed 20 h?.
So the of 95% is 19/24 and 99%is 33/40 And 34/40 means diffelction from mean value. That is
Given that the standard of life time is 100h And life is not exceed by 20 h So maximum life time will be 120 h And minimum life time will be 80 h So a) if he is 95 % confident than P(x<20) is 100/120 =5/6 As he 95% confident than 5/6*95/100 5/6*19/20 19/24 B) 99% So it will be equal to 5/6*99/100 33/40 C) 99.73 So it will be equal to 5/6*99.73/100 Approx 34/40
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