The half-life of calcium-48 is 43 years it take a 44 mg sample to decay to a mass of 11 mg 86 years
Half life is the interval of time required for one-half of the atomic nuclei of a radioactive sample to decay
Here given data is
t1/2 = 43 year
N₀ = 44mg
Nt = 11 mg
t = ?
So the formula is
Nt = N₀ (1/2)t/t1/2
11 mg = 44mg(1/2)t/43
11 mg/ 44mg = (1/2)t/43
log (0.25) = t/43 log (1/2)
t = 43 log (0.25)/log 0.5
t = 86 years
86 years will it take a 44 mg sample to decay to a mass of 11 mg
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