In comparison to her classmates, Kay did better in quiz 2.
According to the question,
Kay scored 15 on Quiz 1 which had a mean of 12 and a standard deviation of 2.4
= Z-score = 15 - 12/ 2.4 = 1.25
She scored 14 on Quiz 2 which had a mean of 11 and a standard deviation of 2
= Z-score = 14 - 11/ 2 = 1.5
As we can see the Z-score of Quiz 2 is more than the Z-score of Quiz 1 hence Kay did better in Quiz 2.
To learn more about statistics, mean, median, and mode,
https://brainly.com/question/29342780
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