The solution of the equation is; (-1, 0), (0, 8) (0.5, 9) (2, 0), and (1.5, 5) The Graph of the given function is attached below.
How to find the solution to a standard quadratic equation?
A quadratic equation is the second-order degree algebraic expression in a variable. the standard form of this expression is ax² + bx + c = 0 where a. b are coefficients and x is the variable and c is a constant.
Then its solutions are given as
[tex]x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}[/tex]
WE have been given a quadratic equWeion as;
[tex]-4x^{2 }+4x+8[/tex]
Now divide the equation by 2 then we get;
[tex]-x^{2 }+ 2x+ 4[/tex]
Then the solution of the equation are;
(-1, 0), (0, 8) (0.5, 9) (2, 0) and (1.5, 5)
The Graph of the given function is attached below.
Learn more out quadratic equations here:
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