pat wants to move a 11.3 kg box across a level floor. the coefficient of kinetic friction between the box and the floor is 0.41. after pat has started the box moving, what strength push force (in n) will be required to keep the box moving at a constant speed?

Friction is the force that resists relative motion as elements of solid surfaces, fluid layers, and materials slide over each other. A type of contact force that exists between contact surfaces.

We know that;

Fₙ = m × a

Where, Fₙ = Net force

m = mass of the object (11.3 kg)

a = acceleration

Since the box is moving with a constant speed which means there is no acceleration.

Fₙ = 11.3 × 0

Fₙ = 0

Now,

Fₓ = μmg

Where, Fₓ = Friction force

μ = coefficient of kinetic friction (0.41)

m = mass of the box (11.3 kg)

g = gravitational acceleration (9.8m/s²)

Fₓ = 0.41 × 11.3 × 9.8

Fₓ = 45.4 N

We know that,

Fₙ = Fₐ - Fₓ

Where, Fₙ = Net force

Fₐ = Applied force

Fₓ = Friction force

Since Fₙ = 0, then:

0 = Fₐ - 45.4

Fₐ = 45.4 N

Therefore, if the kinetic friction force is equal to the applied force, the acceleration will be zero and the body will move with constant velocity.

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