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A parallel circuit ha a 12V power pack. It ha 2 branche each with a light bulb on. What i the potential difference of each of the light bulb?

Respuesta :

The potential difference between each of the light bulbs will be 6.

According to ohms law,

V=IR

V=12v

R=2 (2 branches draw current so they serve as resistance)

I=V/R

=12/2

=6 A

This current will serve as the voltage difference between each light bulb.

The potential difference may be a degree of the sum of vitality exchanged between two points in a circuit. Potential contrast is additionally known as voltage and is measured in volts (V).

The potential difference over a component is measured by employing a voltmeter set in parallel with the component. Voltage, moreover, known as electric weight, electric pressure, or (electric) potential contrast, is the distinction in electric potential between two focuses.

In an inactive electric field, it compares to the work required per unit of charge to move a test charge between the two focuses.

Learn more about the potential difference at

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