Respuesta :
The new speed while holding the sack is v₂ = 4.32 m/s as per the given mass and velocity.
What is meant by velocity?
Velocity is the rate of change in position of a moving object as observed from a specific frame of reference and measured by a specific time standard.
Given,
The mass of first object m₁=55kg
The mass of second object m₂=5kg
The velocity of first object v₁=4.5m/s
The velocity of second object v₂=?
The mass of the object that is dropped m₃=2.5 kg
When two bodies contact, the momentum of the two bodies before the collision equals the momentum after the collision, according to the law of conservation of momentum.
Pa= Pb
Where Pa denotes the momentum before the impact and Pb denotes the momentum after the collision.
When we apply this law to the preceding situation, we get Momentum before collision= Momentum after collision.
Momentum before impact = ( m₁+m₂) x v₁ = (55+5)x 4.5 = 270 Kg m/s
Momentum after impact = ( m₁+m₂+m₃) x v₂ = (55+5+2.5) x v₂
We now understand that momentum before contact equals momentum after impact:
270 = 62.5 v₂
v₂ = 4.32 m/s
The new speed while holding the sack is v₂ = 4.32 m/s
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