Respuesta :
The percent of chloride ion in a sample if 2. 500 g of the sample produces 1. 750 g of AgCl when treated with excess ag⁺ is 17.2%
The percent of chloride can be calculate as follow:
Mass of AgCl precipitated = 1.750 g
Molar mass of AgCl = 143.32 g/mol
Molar mass of Chlorine atom = 35.45 g/mol
Asume, all the chlorine in the sample is precipitated to silver chloride. So, the mass of chlorine in silver chloride will be equal to the mass of chlorine present in the sample.
To calculate the mass of chlorine in given mass of AgCl, we apply unitary method:
In 143.32 g of silver chloride, mass of chlorine present is 35.45 g
So, in 1.3487 g of silver chloride, mass of chlorine present will be =
35.45g/143.32 g * 1.750 g = 0.43 g
To calculate the percentage composition of chlorine in pure chloride compound, as follows:
Mass of pure chloride compound = 2.500 g
Mass of chlorine = 0.43 g
% Chlorine = 0.43/2.5 *100
% Chlorine = 17.2 %
Therefore, the mass percentage of chloride in pure chloride compound is 17.2%
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