Cora is flipping three coins at once. The probability that the number of landed coins showing "heads" is less than 3 is 0.875
Probability is a measure how likely an event occurs. Probability of an event A is calculated as:
P(A) = number of ways A can occur / total possible outcomes
Let A and B be independent events, then the followings hold:
P (A and B) = P (A∩B) = P(A) + P(B)
P (A or B) = P (A∪B) = P(A) · P(B)
P (not A) = P(Ā) = 1 - P(A)
In the given problem, H is an event where the number of landed coins showing heads.
The probability distribution for H is:
P(H = 0) = 0.125
P(H = 1) = 0.375
P(H = 2) = 0.375
P(H = 3) = 0.125
The probability of three coins show heads less than 3 is:
P(H < 3) = 1 - P(H=3)
= 1 - 0.125 = 0.875
It can also be obtained using:
P(H<3) = P(H=0) + P(H=1) + P(H=2)
= 0.125 + 0.375 + 0.375
= 0.875
Hence, the probability of three coins show heads less than 3 is 0.875.
Complete question:
Cora is playing a game that involves flipping three coins at once. Let the random variable H be the number of coins that land showing "heads". Here is the probability distribution for H:
P(H = 0) = 0.125, P(H = 1) = 0.375, P(H = 2) = 0.375, P(H = 3) = 0.125. What is the probability H is less than 3.
Learn more about probability here:
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