A particularly scary roller coaster contains a loop-the-loop in which the car and rider are completely upside down. If the radius of the loop is 13. 2 m, with what minimum speed must the car traverse the loop so that the rider does not fall out while upside down at the top? assume the rider is not strapped to the car.

Respuesta :

with 13.06 meters per second minimum speed, car traverse the loop so that the rider does not fall out while upside down at the top.

What is centripetal force?

A net force called a centripetal force keeps an object moving in a circle by acting on it.

Given,

Radius of Loop, r = 13.2 m

without the strap, roller coaster must have complete the loop.

At highest point

weight will provide centripetal force just to complete the loop

Thus mg = mv²/r

where v = minimum velocity possessed by roller coaster in order to cover the loop

v =  [tex]\sqrt{gr}[/tex]

v = [tex]\sqrt{9.8 X 13.2}[/tex]

v = [tex]\sqrt{129.36}[/tex] = 13.06 m

Therefore, with 13.06 meters per second minimum speed, car traverse the loop so that the rider does not fall out while upside down at the top.

To learn more about centripetal force

Here: https://brainly.com/question/29215281

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With 13.06 meters per second minimum speed, car traverse the loop so that the rider does not fall out while upside down at the top.

What is centripetal force?

A net force called a centripetal force keeps an object moving in a circle by acting on it.

Given,

Radius of Loop, r = 13.2 m

without the strap, roller coaster must have complete the loop.

At highest point

weight will provide centripetal force just to complete the loop

Thus mg = mv²/r

where v = minimum velocity possessed by roller coaster in order to cover the loop

v =  √9r

v = √9.8×13.2

v = √129.36 = 13.06 m

Therefore, with 13.06 meters per second minimum speed, car traverse the loop so that the rider does not fall out while upside down at the top.

To learn more about centripetal force

brainly.com/question/29215281

#SPJ4