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A scuba diver's tank contains 1. 47 moles of o2 and 5. 53 moles of he at the end of a dive. If the pressure of the gas mixture is 12. 1 atm, what is the partial pressure of he in the tank?.

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Eduard22sly

The partial pressure of helium, He in the tank, given that the tank contains 1.47 mole of O₂ and 5.53 moles of He, is 9.559 atm

How do I determine the partial pressure of He?

To calculate the partial pressure of He in the tank, we must first obtain the mole fraction of He. Details on how to obtain the mole fraction of He is shown below:

  • Mole of O₂ = 1.47 mole
  • Mole of He = 5.53 moles
  • Total mole = 1.47 + 5.53 = 7 moles
  • Mole fraction of He =?

Mole fraction of He = Mole of He / total mole

Mole fraction of He = 5.53 / 7

Mole fraction of He = 0.79

Now, we can obtain the partial pressure of He. This is illustrated below:

  • Mole fraction of He = 0.79
  • Total pressure in tank = 12.1 atm
  • Partial pressure of He in tank =?

Partial pressure = mole fraction × total pressure

Partial pressure of He = 0.79 × 12.1

Partial pressure of He = 9.559 atm

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