a 1140-kg van, stopped at a traffic light, is hit directly in the rear by a 745-kg car traveling with a velocity of 1.77 m/s. assume that the transmission of the van is in neutral, the brakes are not being applied, and the collision is elastic. what is the final velocity of (a) the car and (b) the van?

Respuesta :

Applying the conservation of momentum law we find the final velocity of

                        a) the car = 0.37 m/s in the opposite direction.

                        b) the van = 1.39 m/s

Define elastic collision between particles?

  • An elastic collision is defined as the collision which when happens between bodies there is no net loss of kinetic energy in the system.
  • In elastic collisions, both kinetic energy and momentum of the bodies are conserved.

The given informations in the question are-

Mass of van = mv = 1140 kg

Mass of car = mc = 745 kg

Initial velocity of car = v1_i =  2.25 m/s

Applying conservation of momentum, the final velocity of the car is found out using the formula,

v1_f = (mc - mv) x v1_i / (mc + mv)

Putting the values we get,

v1_f = (745 - 1140) x 1.77 / (745 + 1140)

       = - 395 x 1.77 / 1885

       = - 0.37  m/s

The negative sign indicates that after collision it is moving in the opposite direction to its initial speed.

The final velocity of the van, is found out using the formula,

v2_f = 2 x mc x v1_i / (mv +mc)

Putting the values we get,

v2_f  = 2 x 745 x 1.77 / (745 + 1140)

        =  1.39 m/s

Hence, the final velocity of

                        a) the car = 0.37 m/s in the opposite direction.

                         b) the van = 1.39 m/s

To learn more about elastic collision from the given link

https://brainly.com/question/2356572

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