Applying the conservation of momentum law we find the final velocity of
a) the car = 0.37 m/s in the opposite direction.
b) the van = 1.39 m/s
Define elastic collision between particles?
The given informations in the question are-
Mass of van = mv = 1140 kg
Mass of car = mc = 745 kg
Initial velocity of car = v1_i = 2.25 m/s
Applying conservation of momentum, the final velocity of the car is found out using the formula,
v1_f = (mc - mv) x v1_i / (mc + mv)
Putting the values we get,
v1_f = (745 - 1140) x 1.77 / (745 + 1140)
= - 395 x 1.77 / 1885
= - 0.37 m/s
The negative sign indicates that after collision it is moving in the opposite direction to its initial speed.
The final velocity of the van, is found out using the formula,
v2_f = 2 x mc x v1_i / (mv +mc)
Putting the values we get,
v2_f = 2 x 745 x 1.77 / (745 + 1140)
= 1.39 m/s
Hence, the final velocity of
a) the car = 0.37 m/s in the opposite direction.
b) the van = 1.39 m/s
To learn more about elastic collision from the given link
https://brainly.com/question/2356572
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