When two blocks are sliding on a frictionless surface ,Then speed of the two blocks after the collision is 2V.
A Frictionless surface refers to that kind of surface where the force acting on any object which makes it difficult for the object to slide is almost zero or negligible,
As per the given data
The mass of smaller box= m and velocity =v
And the mass of larger box =M and velocity =V
So the momentum ps=mv and pL= MV
And combined mass of both the boxes will be M+m
Hence the combined velocity after collision = Momentum of combination/Mass of combination
V=MV+mv/M+m
Then V =V+v
V=2V
Hence, When t wo blocks are sliding on a frictionless surface ,Then speed of the two blocks after the collision is 2V.
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