Respuesta :
For the given data about about inscribed right circular cone of height 2.5 units and radius 7.5 units then the dimensions of the cylinder which has maximum volume is given by height = 0.83 units and radius 5 units.
As given in the question,
Height of the right circular cone = 2.5 units
And radius of right circular cone = 7.5 units
Let r be the radius of the cylinder and h be the height of the cylinder.
Volume of a cylinder 'V' = π r² h
Cylinder is inscribed in right circular cone
From origin edge cylinder is inscribed at x distance in right circular cone.
r = 7.5 - x
h = (2.5 /7.5) x
= x/3
V = π ( 7.5 - x )² ( x / 3)
⇒ V = π ( x² -15x + 56.25 ) (x/3)
⇒ V = (π /3)( x³ - 15x² + 56.25x)
For maximum volume ,
dV/dx = 0
dV/dx = (π/3)( 3x² -30x + 56.25)
(π/3) ≠ 0
⇒ 3x² -30x + 56.25 = 0
⇒ 3 ( x² -10x + 18.75) = 0
3 ≠ 0
⇒ x² -10x + 18.75 = 0
x = [ - (-10) ± √ (-10)² -4(1)(18.75)]/2(1)
⇒ x = [ 10 ± √ 100 -75]/2
⇒ x= ( 10 ± 5 ) / 2
⇒ x = 7.5 or 2.5
As r = 7.5 -x
Hence x ≠ 7.5
r = 7.5 -2.5
= 5 units
h = x/3
= 2.5/3
= 0.8333 units
Therefore, for the given data about about inscribed right circular cone of height 2.5 units and radius 7.5 units then the dimensions of the cylinder which has maximum volume is given by height = 0.83 units and radius 5 units.
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