Respuesta :
1.55 x 10⁻⁶ F is the capacitance if both slices of dielectric material are placed between the plates.
What is dielectric constant?
An indicator of a substance or material's capacity to store electrical energy is its dielectric constant. It is a measurement of how much an object can hold or concentrate an electric flux. Dielectric constant is defined mathematically as the ratio of a material's permittivity to the permittivity of free space.
For one slice, we have
thickness, d₁ = 0.0025 x 10⁻³ m
dielectric constant, k₁ = 6.2
breakdown field strength, E₁ = 7.15 x 10⁶ V/m
For second slice, we have
thickness, d₂ = 0.0085 x 10⁻³ m
dielectric constant, k₂ = 10.7
breakdown field strength, E₂ = 3.15 x 10⁶ V/m
(a) The capacitance of each possible choice which is given as :
For one slice ; C₁ = k₁o A/d₁ = (6.2) (8.85 x 10⁻¹² C²/Nm²) (0.047 m²) / (0.0025 x 10⁻³ m)
C₁ = 1031.5 x 10⁹ F
C₁ = 1.03 x 10⁻⁶ F
For second slice; C₂ = k₂0 A / d₂ = (10.7) (8.85 x 10-12 C²/Nm²) (0.047 m²) / (0.0085 x 10⁻³m)
C₂ = 523.6 x 10⁻⁹ F
C₂ = 5.23 x 10⁻⁷ F
{one slice will have a greater capacitance than second slice }
(b) The maximum working voltage for each capacitor is given as :
For one slice; E₁ = V₁ /d₁⇒ (7.15 x 10⁶ V/m) = V₁ / (0.0025 x 10⁻³ m)
V₁ = 17.8 V
For second slice; E₂ = V₂/d₂ (3.15 x 10⁶ V/m) = V₂ / (0.0085 x 10⁻³ m)
V₂ = 26.7 V
If both slices of dielectric material are placed b/w the plates, then the capacitance will be
given as:
Ctotal = C₁ + C₂ = [(1.03 x 10⁶ F) + (5.23 x 10⁻⁷ F)]
Ctotal = 1.55 x 10⁻⁷ F
To know more about dielectric constant visit:
https://brainly.com/question/13265076
#SPJ4
