The standard form of a quadratic function is y = 3/2x² + 17/2x - 7
How to determine the quadratic equation?
From the question, the points on the quadratic equation are given as
(2,4), (3,5) and (4,3)
The standard form of a quadratic equation is represented as
y = ax² + bx + c
So, we have
Point (2,4):
4a + 2b + c = 4
Point (3,5):
9a + 3b + c = 5
Point (4,3):
16a + 4b + c = 3
Solving using an online calculator. we have
a = 3/2, b = 17/2 and c = -7
Substitute a = 3/2, b = 17/2 and c = -7 in y = ax² + bx + c
y = 3/2x² + 17/2x - 7
Hence, the equation is y = 3/2x² + 17/2x - 7
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