a sample of he gas at 3.0 l and 5.6 atm was combined with a sample of ne gas at 4.5 l and 3.6 atm in a single flask of volume 9.0 l at constant temperature. what is the total pressure in the flask assuming that the initial pressure was 0 atm?

Respuesta :

P = 3.67 atm is the total pressure in the flask assuming that the initial pressure was 0 atm .

What is Ideal gas law ?

The ideal gas law (also called the perfect gas law), the relationship between the pressure P, volume V, and temperature T of a gas in the boundary region between low pressure and high temperature. Gas molecules move almost independently. each other .

PV = nRT, where n is the number of moles of gas and R is the universal (or perfect) gas constant, 8.31446261815324 joules/kelvin/mol (the universal gas constant is defined as Avogadro's number NA multiplied by Boltzmann's constant k) . ) In the International System of Units, energy is measured in joules, volume in cubic meters (m3), force in newtons (N), and pressure in pascals (Pa). where 1 Pa = 1 N/m2. A force of 1 Newton moving a distance of 1 meter does 1 Joule of work. Therefore, the product of both PV and nRT has the dimension of work (energy).

For He:  PV = nRT and n = PV/RT

n = (5.6 atm)(3.0 L)/(0.0821 Latm/Kmol)(298K) = 0.687 moles He

For Ne:  PV = nRT and n = PV/RT

n = (3.6 atm)(4.5 L)/(0.0821 Latm/Kmol)(298K) = 0.662 moles Ne

Total moles = 0.687 + 0.662 = 1.349 moles

PV = nRT

P = nRT/V

P = (1.349 mol)(0.0821 Latm/Kmol)(298 K)/9.0 L

P = 3.67 atm

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