contestada

a 45.0-$kg$ body is moving in the direction of the positive x axis with a speed of 282 $m/s$ when, owing to an internal explosion, it breaks into three pieces. one part, whose mass is 10.0 $kg$, moves away from the point of explosion with a speed of 376 $m/s$ along the positive y axis. a second fragment, whose mass is 5.0 $kg$, moves away from the point of explosion with a speed of 378 $m/s$ along the negative x axis. what is the speed of the third fragment? ignore effects due to gravity.

Respuesta :

The speed of the third fragment after explosion is 0.004i - 0.009j.

The mass of the body initially is 45 Kg. It is moving with a speed of 282 m/s.

It explodes and one of it fragment of mass 5 Kg moved with speed of 378 m/s in -x direction. The second fragment of mass 10 kg goes into y direction with a speed of 376 m/s.

The mass of the third fragment is (45-10-5)kg

Mass = 30 kg. Let us assume that it is moving with a speed V.

Now, as there is no external force, so, the momentum will be conserved,

So, we can write,

Initial momentum = final momentum

So,

45(282) = 10(376)j - 5(378)i + 30V

Solving further,

V = 0.004i - 0.009j

So, the speed of the third fragment is 0.004i - 0.009j.

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