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a dog (mass 14.0 kg) sits on a sled (mass 6.1 kg) that is being pushed with a force of 48.5 n on a flat snowy surface. if the acceleration of both is 1.92 , what is the coefficient of kinetic friction for the sled sliding on the snow?

Respuesta :

If the acceleration of both is 1.92, the coefficient of kinetic friction is 0.198 for the sled sliding on the snow.

What is coefficient of kinetic friction?

It is the ratio of the friction force to the normal force experienced by a body moving on a dry, non-smooth surface.

Now, let's calculate the coefficient of kinetic friction

Uk = Frictional force / N
Here, N = (m+M)*g, where m and M are respectively mass of the dog and the sled.

N = (6.1 + 14) * 9.8 = 196.98N

Frictional force = (m+M)*a

= (5.7 + 14.6) * 1.92
= 38.976N

So Uk = Frictional force / N

= 38.976 / 196.98 = 0.198


So, the coefficient of kinetic friction based on the calculation will be 0.198 for the sled sliding on the snow.

Learn more about coefficient of kinetic friction https://brainly.com/question/19392943

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