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Hemophilia is another example of a x-linked disease caused when a recessive allele (xh) is expressed. If a normal male reproduces with a heterozygous normal female, what are the expected genotypes and phenotypes? will any of their daughters develop hemophilia? as in the previous question, you must also give the gender of the child in your genotype and phenotype descriptions here.

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chemisst

No one of the daughters will develop hemophilia.

Consider allele for a normal person = XH- and hemophilic person = Xh-The genotype of a heterozygous woman is XHXh, whereas that of a normal man is XHY.

XHXh × XHY

The punnet square which is attached as an image has information about the predicted genotype and characteristics for XhY (hemophilic man).

XHXH = normal female

XHY = normal male

XHXh = carrier female which is phenotypically normal

XhY = hemophilic male

The genotypes of the daughters are XHXh and XHXH. Since nobody of the daughters possesses the XhXh genotype, which is required for a female to acquire hemophilia, all of the daughters are phenotypically normal.

If you want to learn more about hemophilia visit;

https://brainly.com/question/18916729

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