The NaOH solution with percent of mass 15% has a total volume of 520.98 cc.
We need to know about percent of mass to solve this problem. The percent of mass explains how much part of the solid part (solute) is in the solution. The percent of mass can be written as
x = m / M
where m is the mass of the solute and M is the total mass of the solution.
From the question above, the given parameters are
x = 15%
m = 85 g
ρwater = 1 g/cc
ρNaOH = 2.13 g/cc
Find the volume of solid NaOH
VNaOH = m / ρNaOH
VNaOH = 85 / 2.13
VNaOH = 39.31 cc
Find the total mass of the solution
x = m / M
15% = 85 / M
M = 566.67 g
Hence, the mass of water
mwater = 566.67 - 85 = 481.67 g
Water volume should be
Vwater = mwater / ρwater
Vwater = 481.67 / 1
Vwater = 481.67 cc
Hence, the total volume of the solution is
Vtotal = Vwater + VNaOH
Vtotal = 481.67 + 39.31
Vtotal = 520.98 cc
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