The molarity of the H₂O₂ in the reaction mixture will be 0.063 M
The molarity of the KI in the reaction mixture will be 0.071 M
Volume of H₂O = 55 ml
Volume of H₂O₂ (V1) = 5.0 ml
Volume of KI = 10.0 (V1) ml
Molarity of H₂O₂ (initial M1) = 0.88 M
Molarity of KI (initial M1) = 0.50 M
Molarity of H₂O₂ (final M2) = ?
Molarity of KI (final M2) = ?
Calculate the total volume V2
V2 = 55.0 ml + 5.0 ml + 10.0 ml
V2 = 70.0 ml
Calculate the molarity of H₂O₂ by using the following equation:
M1 × V1 = M2 × V2
Rearrange it for M2
M2 = M1 × V1 / V2
Put the values
M2 = 0.88M × 5ml / 70ml
M2 = 0.063M
Calculate the molarity of KI by using the following equation:
M1 × V1 = M2 × V2
Rearrange it for M2
M2 = M1 × V1 / V2
Put the values
M2 = 0.5 M × 10 ml / 70ml
M2 = 0.071 M
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