Respuesta :
If the elevator has an acceleration of
a)2.10m/sec² up then scale reads 880.35N
b)2.10 m/sec² down then scale reads 569.64N
c)0m/sec² then scale reads 725N for 725-n organism sits on a scale on the floor of an elevator.
I will assume the man weighs 725 N and the 2 accelerations are
2.10m/sec² up and down. If the elevator is stationary, the scale would be applying an upward force of 725 N to hold the man in the equilibrium state.
a. When accelerating upwards, the scale have to apply an extra upward force. For the next bit, I will need the man's mass.
=>m=weight/g=725N/9.8m/sec² = 73.9kg
So, the extra upward force to accelerate the man upwards is given by
=>F = ma
=>F = (73.9×2.10)=155.35N
The scale reading is the measurement of the upward force the scale is providing for whoever is standing there.
When accelerating the man upwards, the total upward force is
725N+155.35N=880.35N
b) When accelerating the man downwards, the total downward force is
725 -155.35N=569.64N
c)When acceleration is zero, the total force is 725N
Hence, the scale readings are a)880.35N, b)569.64N c)725N
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