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1000 kg car is driving forward with a speed of 25 m/s. it comes to rest in a distance of 100m what is its change in kinetic energy during this process

Respuesta :

If a 1000 kg car is driving forward with a speed of 25 m/s and it comes to rest in a distance of 100m, the change in kinetic energy during this process is - 312.5 KJ

KE = 1 / 2 m v²

KE = Kinetic energy

m = Mass

v = Velocity

m = 1000 kg

Initially,

v = 25 m / s

KEi = 1 / 2 * 1000 * 25²

KEi = 312500 J

Finally,

v = 0, since the object comes to rest.

KEf = 1 / 2 * 1000 * 0

KEf = 0

ΔKE = KEf - KEi

ΔKE = Change in kinetic energy

ΔKE  = 0 - 312500

ΔKE = - 312500

ΔKE = - 312.5 KJ

Therefore, the change in kinetic energy during this process is - 312.5 KJ

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