a uniform rod of length 12 m has a pivot located at the center of the rod. a weight of 6 n is applied to one end of the rod. at what distance from the pivot must a 200 n weight be placed in order for the rod to be balanced?

Respuesta :

The distance from the pivot must a 200 n weight be placed in order for the rod to be balanced is 0.18 m.

Torque is the rotational equation of linear force. it's also called the instant, a moment of force, rotational force, or turning effect, depending on the sphere of taking a look at. It represents the capability of pressure to supply an alternate inside the rotational motion of the body.

Calculation:-

at equilibrium

Net torque τ net = 0

6 N × 6m = 200 N × Xm

 X = 36/200 m

   = 0.18 m

Torque is a measure of the pressure that can reason an object to rotate about an axis. just as pressure is what causes an item to accelerate in linear kinematics, torque is what causes an object to gather angular acceleration. Torque is a vector quantity.

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