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the block of mass 3.17134 kg has an acceleration of 4.9 m/s^2 as shown. What is the magnitude of F? Assume the acceleration due to gravity is 9.8 m/s^2 and the surface is frictionless. Answer in units of N.

the block of mass 317134 kg has an acceleration of 49 ms2 as shown What is the magnitude of F Assume the acceleration due to gravity is 98 ms2 and the surface i class=

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onyebuchinnaji

The magnitude of the applied force is determined as 16.7 N.

What is the magnitude of the force F?

The magnitude of force F is calculated by applying Newton's second law of motion.

F cos θ = ma

where;

  • F is the magnitude of the applied force
  • θ is the angle of inclination of the applied force
  • m is the mass of the block
  • a is the acceleration of the block

F cos(23) = 3.171(4.9)

0.92F = 15.54

F = 15.54 / 0.92

F = 16.7 N

Thus, the magnitude of the force depends on the acceleration, mass and acceleration of the block, as well as the angle of inclination of the applied force.

Learn more about applied force here: https://brainly.com/question/2733221

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